16*(x^2-36)/x=0

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Solution for 16*(x^2-36)/x=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(16*(x^2-36))/x = 0

( 16 )

16 = 0

x belongs to the empty set

( x^2-36 )

1*x^2 = 36 // : 1

x^2 = 36

x^2 = 36 // ^ 1/2

abs(x) = 6

x = 6 or x = -6

x in { 6, -6 }

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